Sunday, December 13, 2020

Print name of each digit of a number in Java

 Challenge is to write a method to print the passed number using words for each of the digits. If the number is negative then print "Invalid Value". 

I simply used the String manipulations in Java to resolve this issue with aid of a Switch statement to identify each digit and get the corresponding name of the digit.

Below is my working solution and I hope it is helpful.

public class NumberToWords {
public static void numberToWords(int number){
String resultString = "";
if(number < 0){
resultString = "Invalid Value";
}else{
String numberString = String.valueOf(number);

for(int i=0; i<numberString.length(); i++){
int currentNumber = Character.getNumericValue
(numberString.charAt(i));

resultString = resultString +
getNameOfNumber(currentNumber) + " ";
}
}
System.out.println(resultString);
}

public static String getNameOfNumber(int num){
String numberName = "";
switch (num){
case 0 :
numberName = "Zero";
break;
case 1:
numberName = "One";
break;
case 2:
numberName = "Two";
break;
case 3:
numberName = "Three";
break;
case 4:
numberName = "Four";
break;
case 5:
numberName = "Five";
break;
case 6:
numberName = "Six";
break;
case 7:
numberName = "Seven";
break;
case 8:
numberName = "Eight";
break;
case 9:
numberName = "Nine";
break;
default:
numberName = "Invalid";
break;
}
return numberName;
}
}



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